Distance from Blandinsville, IL to Seaton, IL
Driving distance between Blandinsville, IL and Seaton, IL is 57.49 miles (or 92.53 kilometers). This guide provides essential information to help you plan effectively for this trip.
If you drove an average car with a fuel efficiency of about 25 miles per gallon (mpg), you would be using approximately 0.04 gallons of gas per mile, and the gas would cost you around $, since you would need about gallons of fuel.
Estimated travel time
Leaving from Blandinsville, IL you would reach Seaton, IL in about 1 hour 16 mins if you keep an average speed of 65 miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from Blandinsville, IL to Seaton, IL in which you can see the origin and destination points marked with A (Blandinsville) and B (Seaton) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in Blandinsville, IL and Seaton, IL as well as every other town you may pass by on your way.
Fuel consumption if you drive from Blandinsville, IL to Seaton, IL
To cover the 57.49 mi that separate Seaton from Blandinsville you are going to need between of fuel, considering you drive an average car (25 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from Blandinsville, IL to Seaton, IL
Depending on the fuel efficiency level of your car, driving from Blandinsville to Seaton will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.
Note: This price is subject to change based on current gas rates.
