Distance from Lower Waterford, VT to Lunenburg, VT
Driving distance between Lower Waterford, VT and Lunenburg, VT is 25.18 miles (or 40.52 kilometers). If you drove an average car (using about 3.6 gallons of gas per mile), the gas would cost you around $, since you would need about gallons of fuel.
Leaving from Lower Waterford, VT you would reach Lunenburg, VT in about 34 minutes if you keep an average speed of miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from Lower Waterford, VT to Lunenburg, VT in which you can see the origin and destination points marked with A (Lower Waterford) and B (Lunenburg) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in Lower Waterford, VT and Lunenburg, VT as well as every other town you may pass by on your way.
Fuel consumption if you drive from Lower Waterford, VT to Lunenburg, VT
To cover the 25.18 mi that separate Lunenburg from Lower Waterford you are going to need between of fuel, considering you drive an average car (30 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from Lower Waterford, VT to Lunenburg, VT
Depending on the fuel efficiency level of your car, driving from Lower Waterford to Lunenburg will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.