Distance from North Troy, VT to Sealy, TX
Driving distance between North Troy, VT and Sealy, TX is 2,051.34 miles (or 3,301.30 kilometers). This guide provides essential information to help you plan effectively for this trip.
If you drove an average car with a fuel efficiency of about 25 miles per gallon (mpg), you would be using approximately 0.04 gallons of gas per mile, and the gas would cost you around $, since you would need about gallons of fuel.
Estimated travel time
Leaving from North Troy, VT you would reach Sealy, TX in about 1 day 8 hours if you keep an average speed of 65 miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from North Troy, VT to Sealy, TX in which you can see the origin and destination points marked with A (North Troy) and B (Sealy) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in North Troy, VT and Sealy, TX as well as every other town you may pass by on your way.
Fuel consumption if you drive from North Troy, VT to Sealy, TX
To cover the 2,051.34 mi that separate Sealy from North Troy you are going to need between of fuel, considering you drive an average car (25 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from North Troy, VT to Sealy, TX
Depending on the fuel efficiency level of your car, driving from North Troy to Sealy will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.
Note: This price is subject to change based on current gas rates.
