Distance from Saukville, WI to Saginaw, OR
Driving distance between Saukville, WI and Saginaw, OR is 2,238.07 miles (or 3,601.83 kilometers). If you drove an average car (using about 3.6 gallons of gas per mile), the gas would cost you around $, since you would need about gallons of fuel.
Leaving from Saukville, WI you would reach Saginaw, OR in about 1 day 8 hours if you keep an average speed of miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from Saukville, WI to Saginaw, OR in which you can see the origin and destination points marked with A (Saukville) and B (Saginaw) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in Saukville, WI and Saginaw, OR as well as every other town you may pass by on your way.
Fuel consumption if you drive from Saukville, WI to Saginaw, OR
To cover the 2,238.07 mi that separate Saginaw from Saukville you are going to need between of fuel, considering you drive an average car (30 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from Saukville, WI to Saginaw, OR
Depending on the fuel efficiency level of your car, driving from Saukville to Saginaw will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.