Distance from Sebastopol, MS to Swainsboro, GA
Driving distance between Sebastopol, MS and Swainsboro, GA is 516.44 miles (or 831.12 kilometers). This guide provides essential information to help you plan effectively for this long-distance trip.
If you drove an average car with a fuel efficiency of about 25 miles per gallon (mpg), you would be using approximately 0.04 gallons of gas per mile, and the gas would cost you around $, since you would need about gallons of fuel.
Estimated travel time
Leaving from Sebastopol, MS you would reach Swainsboro, GA in about 8 hours 24 mins if you keep an average speed of 65 miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from Sebastopol, MS to Swainsboro, GA in which you can see the origin and destination points marked with A (Sebastopol) and B (Swainsboro) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in Sebastopol, MS and Swainsboro, GA as well as every other town you may pass by on your way.
Fuel consumption if you drive from Sebastopol, MS to Swainsboro, GA
To cover the 516.44 mi that separate Swainsboro from Sebastopol you are going to need between of fuel, considering you drive an average car (25 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from Sebastopol, MS to Swainsboro, GA
Depending on the fuel efficiency level of your car, driving from Sebastopol to Swainsboro will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.
Note: This price is subject to change based on current gas rates.
