Distance from Sheffield Lake, OH to Waldorf, MD
Driving distance between Sheffield Lake, OH and Waldorf, MD is 416.88 miles (or 670.91 kilometers). If you drove an average car (using about 3.6 gallons of gas per mile), the gas would cost you around $, since you would need about gallons of fuel.
Leaving from Sheffield Lake, OH you would reach Waldorf, MD in about 6 hours 43 mins if you keep an average speed of miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from Sheffield Lake, OH to Waldorf, MD in which you can see the origin and destination points marked with A (Sheffield Lake) and B (Waldorf) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in Sheffield Lake, OH and Waldorf, MD as well as every other town you may pass by on your way.
Fuel consumption if you drive from Sheffield Lake, OH to Waldorf, MD
To cover the 416.88 mi that separate Waldorf from Sheffield Lake you are going to need between of fuel, considering you drive an average car (30 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from Sheffield Lake, OH to Waldorf, MD
Depending on the fuel efficiency level of your car, driving from Sheffield Lake to Waldorf will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.