Distance from Schenectady, NY to Lake Alfred, FL
Driving distance between Schenectady, NY and Lake Alfred, FL is 1,275.08 miles (or 2,052.03 kilometers). This guide provides essential information to help you plan effectively for this trip.
If you drove an average car with a fuel efficiency of about 25 miles per gallon (mpg), you would be using approximately 0.04 gallons of gas per mile, and the gas would cost you around $, since you would need about gallons of fuel.
Estimated travel time
Leaving from Schenectady, NY you would reach Lake Alfred, FL in about 19 hours 57 mins if you keep an average speed of 65 miles per hour, assuming you don’t make any breaks or get stuck in traffic.
This is a map overview of the best driving route from Schenectady, NY to Lake Alfred, FL in which you can see the origin and destination points marked with A (Schenectady) and B (Lake Alfred) respectively as well as blue line along the road route you can take. You can zoom in to see more details, including road numbers and even street names both in Schenectady, NY and Lake Alfred, FL as well as every other town you may pass by on your way.
Fuel consumption if you drive from Schenectady, NY to Lake Alfred, FL
To cover the 1,275.08 mi that separate Lake Alfred from Schenectady you are going to need between of fuel, considering you drive an average car (25 mpg) and , if you drive an SUV or a heavy car (20 mpg). If you drive a fuel efficient car (45 mpg), your consumption will only be .
Cost of driving from Schenectady, NY to Lake Alfred, FL
Depending on the fuel efficiency level of your car, driving from Schenectady to Lake Alfred will cost you between and . An average car would make the trip for . We calculate the route cost using real time average gas prices for the US and other costs such as tolls are not included in this calculation.
Note: This price is subject to change based on current gas rates.
